(2x-3)(3x+4)=6x^2

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Solution for (2x-3)(3x+4)=6x^2 equation:


Simplifying
(2x + -3)(3x + 4) = 6x2

Reorder the terms:
(-3 + 2x)(3x + 4) = 6x2

Reorder the terms:
(-3 + 2x)(4 + 3x) = 6x2

Multiply (-3 + 2x) * (4 + 3x)
(-3(4 + 3x) + 2x * (4 + 3x)) = 6x2
((4 * -3 + 3x * -3) + 2x * (4 + 3x)) = 6x2
((-12 + -9x) + 2x * (4 + 3x)) = 6x2
(-12 + -9x + (4 * 2x + 3x * 2x)) = 6x2
(-12 + -9x + (8x + 6x2)) = 6x2

Combine like terms: -9x + 8x = -1x
(-12 + -1x + 6x2) = 6x2

Add '-6x2' to each side of the equation.
-12 + -1x + 6x2 + -6x2 = 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
-12 + -1x + 0 = 6x2 + -6x2
-12 + -1x = 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
-12 + -1x = 0

Solving
-12 + -1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1x = 0 + 12
-1x = 0 + 12

Combine like terms: 0 + 12 = 12
-1x = 12

Divide each side by '-1'.
x = -12

Simplifying
x = -12

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